https://r2.erweima.ai/mathbot/image/17258651940001fzv8epa.jpg

The problem in the image appears to describe two ships (Ship A and Ship B) initially located at positions \( P \) and \( Q \), with a distance of 36 km between them. The ships start moving simultaneously in different directions: Ship A at a speed of 35 km/h and Ship B at 50 km/h. They move for 90 minutes (1.5 hours). The task asks to calculate various distances.

Here’s how to interpret and approach the problem:

### Step-by-step approach:

1. **Initial Distance Between the Ships:**
   The problem states that the initial distance between Ship A and Ship B is 36 km.

2. **Movement of the Ships:**
   - Ship A moves at a speed of 35 km/h for 90 minutes, or 1.5 hours. The distance covered by Ship A is:
     \[
     d_A = 35 \, \text{km/h} \times 1.5 \, \text{hours} = 52.5 \, \text{km}
     \]
   - Ship B moves at a speed of 50 km/h for 90 minutes, or 1.5 hours. The distance covered by Ship B is:
     \[
     d_B = 50 \, \text{km/h} \times 1.5 \, \text{hours

Two ships, A and B, start from positions P and Q, respectively, with a distance of 36 km between them. They begin moving simultaneously but in different directions. Ship A travels at a speed of 35 km/h, and Ship B travels at 50 km/h. Both ships sail for 90 minutes. The task is to calculate various distances, including how far each ship has traveled and their distance apart after 90 minutes.

Calculate the distance between two ships after 90 minutes of sailing at different speeds using the Pythagorean theorem. Ship A travels at 35 km/h and Ship B at 50 km/h, starting 36 km apart. Includes step-by-step trigonometric and distance calculations. Suitable for Grades 9-11.

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