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The problem is as follows:

You have **3,125 soles** in **5-soles bills**, and you need to make as many equal bundles of these bills as the number of bills in each bundle. The question is to determine the value of each bundle.

### Solution:
1. First, determine how many 5-soles bills there are in total:
   \[
   \frac{3,125}{5} = 625 \text{ bills}
   \]

2. The number of bundles is equal to the number of bills in each bundle. Let this number be \(x\). Therefore, there are \(x\) bundles, and each bundle contains \(x\) bills.

3. The total number of bills is \(x \times x = x^2\). Since the total number of bills is 625, we can set up the equation:
   \[
   x^2 = 625
   \]

4. Solving for \(x\):
   \[
   x = \sqrt{625} = 25
   \]

So, each bundle contains **25 bills**.

5. To find the value of each bundle, multiply the number of bills in a bundle by the value of each bill:
   \[
   25 \times 5 = 125 \text{ soles}
   \]

Thus, the value of each bundle is **S/. 125**.

### Correct Answer:
**D) S/. 125**

Let me know if you would like further details!

Here are 5 related questions for practice:
1. How many bills would there be if the total money was 6,250 soles in 5-soles bills?
2. What would the value of each bundle be if there were 900 soles instead of 3,125?
3. How does the solution change if the bills were 10 soles instead of 5 soles?
4. How many bundles could you make with 500 soles in 5-soles bills?
5. What is the formula for calculating the value of each bundle for any total amount of money?

**Tip:** Always check if the total number of items (in this case, bills) forms a perfect square when you need equal groupings!

Con 3,125 soles en billetes de 5 soles se pueden hacer tantos fajos iguales de estos billetes, como billetes tiene cada fajo. ¿Cuál es el valor de cada fajo?

Learn how to determine the value of each bundle when dividing 3,125 soles into equal bundles of 5-soles bills. The solution involves finding the square root of the total number of bills and multiplying by the bill value. Suitable for Grades 7-9 students.

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