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You have provided the equation: 

\[
11x + 30 = 14x + 21
\]

Let's solve this step by step.

### Step 1: Move all terms involving \( x \) to one side of the equation.
Subtract \( 14x \) from both sides:

\[
11x - 14x + 30 = 21
\]

This simplifies to:

\[
-3x + 30 = 21
\]

### Step 2: Move the constant term to the other side.
Subtract 30 from both sides:

\[
-3x = 21 - 30
\]

Simplifying:

\[
-3x = -9
\]

### Step 3: Solve for \( x \).
Divide both sides by \(-3\):

\[
x = \frac{-9}{-3} = 3
\]

Thus, the solution is \( x = 3 \).

Would you like a detailed breakdown of any specific step or have any further questions?

Here are some related questions you might find useful:

1. How do you solve equations with variables on both sides?
2. Can equations have more than one solution?
3. What are common mistakes when solving linear equations?
4. How do you handle equations with fractions or decimals?
5. What is the next step after solving a linear equation like this?

**Tip:** When solving linear equations, always check your solution by substituting it back into the original equation to ensure both sides are equal.

Learn how to solve the linear equation 11x + 30 = 14x + 21 with a detailed step-by-step breakdown. This problem involves key algebra concepts and is suitable for students in Grades 6-8.

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