Solve for x: 

﻿7 open parentheses 5 x minus 2 close parentheses equals 6 open parentheses 6 x minus 1 close parentheses﻿

To solve the equation:

\[
7(5x - 2) = 6(6x - 1)
\]

### Step 1: Distribute the numbers outside the parentheses

Distribute 7 to both terms inside the first parentheses and 6 to both terms inside the second parentheses:

\[
35x - 14 = 36x - 6
\]

### Step 2: Get all \( x \)-terms on one side of the equation

Subtract \( 35x \) from both sides to move the \( x \)-terms to one side:

\[
-14 = x - 6
\]

### Step 3: Isolate \( x \)

Add 6 to both sides to isolate \( x \):

\[
-14 + 6 = x
\]

\[
x = -8
\]

### Final Answer:

\[
x = -8
\]

Would you like further details or have any questions?

Here are 5 related questions you might find useful:
1. How do you solve equations with variables on both sides?
2. What are some common mistakes to avoid when solving linear equations?
3. How do you check if your solution is correct?
4. How would you solve this equation if fractions were involved?
5. Can you solve a similar equation where the variables are inside absolute value signs?

**Tip:** Always simplify both sides of the equation as much as possible before solving for the variable.

Learn how to solve the equation 7(5x - 2) = 6(6x - 1) with a detailed step-by-step solution. This problem covers key algebraic concepts, including equations, distributive property, and isolation of variables. Suitable for students in Grades 7-9.

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