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The problem reads:

**"Si se suma a 19, la cuarta parte de un número, la suma es 5 veces dicho número. El número es:"**

This can be translated to:

**"If 19 is added to one-fourth of a number, the result is 5 times that number. What is the number?"**

Let's define the unknown number as \( x \). According to the problem, we have the equation:

\[
19 + \frac{1}{4}x = 5x
\]

### Solving the equation:
1. Subtract \( \frac{1}{4}x \) from both sides to combine like terms:

\[
19 = 5x - \frac{1}{4}x
\]

2. Express both terms on the right side with a common denominator (4):

\[
19 = \frac{20}{4}x - \frac{1}{4}x
\]

\[
19 = \frac{19}{4}x
\]

3. Multiply both sides of the equation by 4 to eliminate the fraction:

\[
76 = 19x
\]

4. Finally, divide both sides by 19:

\[
x = \frac{76}{19} = 4
\]

Thus, the number is \( x = 4 \).

Would you like more details or further clarification on any step? Here are some related questions for practice:

1. What happens if the sum is 6 times the number instead of 5?
2. How would the equation change if the fraction was one-third instead of one-fourth?
3. Can you set up a similar equation using a different number added to the fraction of \( x \)?
4. What other methods can be used to solve this type of equation?
5. How would the solution change if 19 was subtracted instead of added?

**Tip:** When solving linear equations with fractions, multiplying the entire equation by the least common denominator (LCD) can simplify the process by eliminating the fractions.

Si se suma a 19, la cuarta parte de un número, la suma es 5 veces dicho número. El número es:

Learn how to solve the linear equation where adding one-fourth of a number to 19 equals five times the number. This problem involves key algebraic concepts, including solving linear equations. Suitable for students in Grades 7-9.

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