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The solution to the system of equations is \( x = 3 \) and \( y = 1 \). 

Therefore, the value of \( x + y \) is:
\[
x + y = 3 + 1 = 4
\]

The correct answer is \( \boxed{4} \).

Would you like more details on the solution process? Here are five related questions to deepen your understanding:

1. How do you solve systems of nonlinear equations using substitution?
2. What are other methods for solving systems of equations, such as matrix methods?
3. How do proportional relationships between equations help in solving such problems?
4. Can you provide a detailed explanation of how to cross-multiply in these equations?
5. What strategies can you use if equations are more complex or involve additional variables?

**Tip:** When working with equations involving fractions, always try to eliminate the denominators early by cross-multiplying to simplify the expressions.

Resuelva: \[ \frac{2x - 3y}{3x - 4y} = \frac{3}{5}, \quad \frac{x - 2}{y + 2} = \frac{1}{3} \]. Luego, halle el valor de \( x + y \).

Learn how to solve a system of two equations involving fractions: \[ \frac{2x - 3y}{3x - 4y} = \frac{3}{5}, \quad \frac{x - 2}{y + 2} = \frac{1}{3} \]. This problem involves algebraic manipulation and the use of cross-multiplication to find the values of x and y, and then calculating their sum.

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