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The image shows a system of linear equations in Vietnamese. It asks to solve the following system of equations:

\[
\begin{cases}
3x + y = 5 \\
x - 2y = -3
\end{cases}
\]

### Step-by-step solution:

1. From the first equation:
   \[
   3x + y = 5 \quad \Rightarrow \quad y = 5 - 3x
   \]
   
2. Substitute \( y = 5 - 3x \) into the second equation:
   \[
   x - 2(5 - 3x) = -3
   \]
   Simplify:
   \[
   x - 2(5) + 6x = -3 \quad \Rightarrow \quad x - 10 + 6x = -3
   \]
   Combine like terms:
   \[
   7x - 10 = -3 \quad \Rightarrow \quad 7x = 7 \quad \Rightarrow \quad x = 1
   \]

3. Substitute \( x = 1 \) back into \( y = 5 - 3x \):
   \[
   y = 5 - 3(1) = 5 - 3 = 2
   \]

Thus, the solution to the system is:
\[
x = 1, \quad y = 2
\]

### Solution:
\[
(x, y) = (1, 2)
\]

Would you like more details or have any questions?

Here are 5 related questions:
1. How can you check if the solution to the system is correct?
2. What methods can be used to solve systems of equations, and how do they compare?
3. Can this system be solved using the substitution method, elimination method, and matrix method?
4. How do graphical methods represent the solution to this system of equations?
5. What is the general form of a system of linear equations with two variables?

**Tip:** Always verify your solution by substituting the values back into the original equations.

Solve the system of equations: 3x + y = 5 and x - 2y = -3.

Learn how to solve the system of linear equations 3x + y = 5 and x - 2y = -3 using the substitution method. This problem covers key algebraic concepts, and step-by-step calculations. Suitable for students in Grades 7-9.

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