Math Problem Statement
那你如何解释我的思路:按照题意,从第2个袋中取到白球的概率是(n+1)/(m+n+1) = (n+1)/S ,取到黑球的概率是m/(m+n+1) = m/S.[为方便起见,设S=m+n+1.] 从第3个袋中取到白球的概率是(n+1)/S^2 + n/S,...,从第N个袋中取到白球的概率是 [1/S^(N-1)] + n∑{k=1,N-1}(1/S^k) = [1/S^(N-1)] + n(1/S)[1-(1/S)^(N-1)] / [1-(1/S)].
Solution
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Math Problem Analysis
Mathematical Concepts
Probability Theory
Conditional Probability
Geometric Series
Formulas
Probability of drawing balls from bags
Geometric series summation
Theorems
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Suitable Grade Level
Advanced Mathematics
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