Math Problem Statement
PEP3_Termo_sem1_2024.pdf
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solucionar problema n1. recordar que la presiones parciales ideales estan dadas por: % presiones parciales ideales Pideal1=exp(123.9120+(-8754.0896/(0+T))+(0.0202)*T+0*T^2+(-18.1*log(T))); %Etanol Pideal2=exp(33.9438+(-6144.6379/(0+T))+(-0.0037)*T+0*T^2+(-2.85*log(T))); %N-octano
Solution
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Math Problem Analysis
Mathematical Concepts
Thermodynamics
Chemical Engineering
Formulas
P_{\text{ideal1}} = \exp\left(123.9120 + \frac{-8754.0896}{T} + 0.0202 \cdot T - 18.1 \cdot \log(T)\right)
P_{\text{ideal2}} = \exp\left(33.9438 + \frac{-6144.6379}{T} - 0.0037 \cdot T - 2.85 \cdot \log(T)\right)
y_i \cdot P = x_i \cdot \gamma_i \cdot P_{\text{ideal i}}
Theorems
UNIFAC Method
Suitable Grade Level
Advanced Graduate Level
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