Math Problem Statement
Tenemos seis bolas y debemos colocarlas al azar en 3 urnas. Calcular la probabilidad de que ninguna urna esté vacía
Solution
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Math Problem Analysis
Mathematical Concepts
Probability
Combinatorics
Inclusion-Exclusion Principle
Formulas
Total number of distributions: 3^6 = 729
Distributions with at least one empty urn: 192
Distributions with two empty urns: 3
Inclusion-Exclusion formula: Total - (At least one empty + Two empty)
Final probability: 540/729 = 20/27
Theorems
Inclusion-Exclusion Principle
Suitable Grade Level
Grades 9-12
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