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The problem asks to evaluate two functions \( f(x) = -3x + 2 \) and \( g(x) = -2x^2 - 3 \), and specifically to find \( f(6) \) and \( g(4) \).

Let's calculate these values:

1. **For \( f(6) \):**
   \[
   f(6) = -3(6) + 2 = -18 + 2 = -16
   \]

2. **For \( g(4) \):**
   \[
   g(4) = -2(4^2) - 3 = -2(16) - 3 = -32 - 3 = -35
   \]

Thus, \( f(6) = -16 \) and \( g(4) = -35 \).

Would you like further explanation or have any other questions?

Here are 5 related questions:
1. How would you calculate \( f(-2) \) and \( g(-1) \)?
2. What are the intercepts of the function \( f(x) \)?
3. Can you find the vertex of the function \( g(x) \)?
4. How does the behavior of \( f(x) \) compare with \( g(x) \)?
5. How do the signs of the coefficients in \( f(x) \) and \( g(x) \) affect the graph?

**Tip:** In function evaluation, always substitute the input value directly into the formula and simplify carefully!

Find f(6) and g(4) given the functions f(x) = -3x + 2 and g(x) = -2x^2 - 3.

Learn how to evaluate the functions f(x) = -3x + 2 and g(x) = -2x^2 - 3 by finding f(6) and g(4). This problem covers key algebraic concepts related to function evaluation. Suitable for students in Grades 7-9.

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