To find the \(x\)-intercept of the line given by the equation \(2x - y = 8\), we need to determine the point where the line crosses the \(x\)-axis. At the \(x\)-intercept, the value of \(y\) is \(0\).

Substitute \(y = 0\) into the equation:

\[
2x - (0) = 8
\]

Simplify to solve for \(x\):

\[
2x = 8
\]

\[
x = \frac{8}{2} = 4
\]

So, the \(x\)-intercept is at the point \((4, 0)\).

Would you like any further details or have any questions?

Here are five related questions you might find interesting:
1. How do you find the \(y\)-intercept of the same equation?
2. What is the slope of the line \(2x - y = 8\)?
3. How would you graph the line \(2x - y = 8\) using the intercepts?
4. How does changing the coefficients in the equation affect the intercepts?
5. What are the intercepts if the equation is \(3x + 2y = 12\)?

**Tip:** The \(x\)-intercept is the point where the graph of an equation crosses the \(x\)-axis, so setting \(y = 0\) is the key step in finding it.

Learn how to find the x-intercept of the line given by the equation 2x - y = 8 with a detailed step-by-step solution. This problem covers key algebraic concepts related to linear equations and coordinate geometry. Suitable for students in Grades 6-8.

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