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### Step-by-step solution:

The graph shows the position of a ball moving horizontally over time, measured in seconds, with its position in meters. We are asked to find two things:

1. **Displacement between 0 and 24 seconds**  
2. **Total distance traveled between 0 and 24 seconds**

#### 1. **Displacement Calculation**
- **Displacement** is the difference between the final and initial positions.
- At \( t = 0 \) seconds, the ball is at \( 0 \) meters.
- At \( t = 24 \) seconds, the ball is at \( -6 \) meters.

So, the **displacement** is:
\[
\text{Displacement} = \text{Final position} - \text{Initial position} = (-6) - (0) = -6 \text{ meters}.
\]

Thus, the displacement is **-6 meters** (indicating a movement to the left).

#### 2. **Distance Calculation**
- **Distance** is the total length of the path traveled, regardless of direction.
- To calculate this, we sum the absolute values of the position changes at each interval:

   - From \( t = 0 \) to \( t = 6 \): Position changes from \( 0 \) to \( 12 \).  
     Distance: \( |12 - 0| = 12 \) meters.
   - From \( t = 6 \) to \( t = 12 \): Position changes from \( 12 \) to \( -3 \).  
     Distance: \( |12 - (-3)| = 15 \) meters.
   - From \( t = 12 \) to \( t = 18 \): Position changes from \( -3 \) to \( -15 \).  
     Distance: \( |-3 - (-15)| = 12 \) meters.
   - From \( t = 18 \) to \( t = 24 \): Position changes from \( -15 \) to \( -6 \).  
     Distance: \( |-15 - (-6)| = 9 \) meters.

So, the **total distance traveled** is:
\[
12 + 15 + 12 + 9 = 48 \text{ meters}.
\]

### Final Answers:
1. **Displacement**: \(-6\) meters
2. **Distance traveled**: \(48\) meters

---

Would you like more details or further clarification? Here are five related questions you might find helpful:

1. What is the difference between displacement and distance in physics?
2. How do you calculate the average velocity from displacement?
3. Can you explain how velocity changes in this scenario?
4. How would the total distance change if the ball moved further?
5. What is the importance of understanding vector vs scalar quantities in kinematics?

**Tip**: Displacement considers direction, while distance ignores it. This makes displacement a vector quantity and distance a scalar one!

Una pelota roja se mueve de manera horizontal en un tubo de 30 m de largo. La posición de la pelota en metros a través del tiempo se muestra a continuación. ¿Cuál es el desplazamiento de la pelota roja entre 0 y 24 segundos? ¿Cuál es la distancia recorrida por la pelota roja entre 0 y 24 segundos?

Aprende a calcular el desplazamiento y la distancia recorrida de una pelota roja en un tubo de 30 metros usando una gráfica de posición-tiempo. La solución cubre conceptos clave de física, como desplazamiento vectorial y distancia escalar. Adecuado para estudiantes de grados 8 a 10.

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