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To determine which posters Smriti can stick on her wall, we need to compare the areas of the posters with the area of the wall.

1. **Area of the wall**: \( 30 \, \text{m}^2 \)

2. **Poster I**:
   - Length: \( 6 \, \text{m} \)
   - Breadth: \( 5 \, \text{m} \)
   - Area: \( 6 \times 5 = 30 \, \text{m}^2 \)

3. **Poster II**:
   - Length: \( 10 \, \text{m} \)
   - Breadth: \( 3 \, \text{m} \)
   - Area: \( 10 \times 3 = 30 \, \text{m}^2 \)

Both posters have an area of \( 30 \, \text{m}^2 \), which matches the area of the wall. Therefore, both posters can fit on the wall.

The correct answer is:
(B) Both Posters I and II as their areas are same as that of the wall.

Would you like any further details or have any questions about this problem?

Here are 5 more questions you can ask:
1. How do you calculate the perimeter of a rectangle?
2. What is the area of a triangle with base 5 m and height 3 m?
3. How do you find the volume of a cylinder?
4. Can you explain how to solve quadratic equations?
5. What are the properties of different types of triangles?

**Tip:** When solving geometry problems, always remember to write down the formulas you need to use and ensure all measurements are in the same units before performing any calculations.

Learn how to solve a geometry problem involving posters and wall area comparison. Calculate the area of rectangles and determine which posters fit on a wall of 30 square meters. Suitable for students in Grades 5-6.

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