triangle R has an area of 80 cm^2 square  has side length of 4 cm.what is the total area of those two shapes

To find the total area of triangle \( R \) and the square:

1. The area of triangle \( R \) is given as \( 80 \, \text{cm}^2 \).
2. The area of the square can be calculated using the formula for the area of a square, \( \text{Area} = \text{side}^2 \). Since the side length of the square is \( 4 \, \text{cm} \), the area of the square is:
   \[
   \text{Area of square} = 4^2 = 16 \, \text{cm}^2
   \]

Now, sum the areas of the two shapes:
\[
\text{Total area} = 80 \, \text{cm}^2 + 16 \, \text{cm}^2 = 96 \, \text{cm}^2
\]

Thus, the total area of the triangle and the square is \( 96 \, \text{cm}^2 \).

Would you like further details or have any questions?

Here are 5 related questions:
1. How do you calculate the area of other types of triangles (e.g., equilateral, isosceles)?
2. What is the formula for the area of other polygons (e.g., rectangle, parallelogram)?
3. How do you find the area of a circle, and how does it compare to a square?
4. If the side of the square doubled, what would the new area be?
5. How can you calculate the perimeter of these shapes?

**Tip:** Always make sure your units are consistent when calculating area and perimeter.

Learn how to calculate the total area of a triangle with an area of 80 cm² and a square with a side length of 4 cm. Step-by-step solution provided, including formulas for triangle and square areas. Suitable for Grades 5-7.

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