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con la fórmula de concentración, resuelve

To solve the problem provided in the image, we can use the formula for concentration after dilution. The problem is about mixing a solution with a known concentration with water and finding the resulting concentration.

### Problem Restatement:
- **Initial volume (\(V_1\))**: 50 mL
- **Initial concentration (\(C_1\))**: 1 M (molar)
- **Final volume (\(V_2\))**: 50 mL (solution) + 30 mL (water) = 80 mL
- **Final concentration (\(C_2\))**: ?

### Formula:
The concentration after dilution is given by:
\[
C_2 = \frac{C_1 \times V_1}{V_2}
\]

### Calculation:
\[
C_2 = \frac{1 \text{ M} \times 50 \text{ mL}}{80 \text{ mL}} = \frac{50 \text{ M} \cdot \text{mL}}{80 \text{ mL}} = 0.625 \text{ M}
\]

### Answer:
The concentration of ammonia in the final solution is **0.625 M**.

Would you like more details on this process, or do you have any questions? 

Here are 5 related questions to expand your understanding:
1. How would the concentration change if more water was added?
2. What would be the concentration if the initial solution was 2 M instead of 1 M?
3. How would you calculate the concentration if you mixed two solutions of different concentrations?
4. How does temperature affect the concentration of a solution?
5. How do you convert molarity to molality?

**Tip:** When diluting a solution, the key idea is that the number of moles of solute remains the same; only the volume changes, which affects the concentration.

Learn how to calculate concentration after dilution using the given problem involving initial and final volumes and concentrations. This problem focuses on practical applications of molarity and dilution calculations.

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