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The problem provided asks to find the concentration of a stock solution of sodium chloride, given that a diluted solution was prepared from it. The relevant formula to use is the dilution formula:

\[
C_1 V_1 = C_2 V_2
\]

Where:
- \( C_1 \) is the concentration of the stock solution (which we need to find),
- \( V_1 \) is the volume of the stock solution used to make the diluted solution,
- \( C_2 \) is the concentration of the diluted solution,
- \( V_2 \) is the total volume of the diluted solution.

### Given:
- \( C_2 = 0.06 \text{ M} \) (concentration of the diluted solution),
- \( V_2 = 50 \text{ ml} \) (volume of the diluted solution),
- \( V_1 = 3 \text{ ml} \) (volume of the stock solution used).

We need to find \( C_1 \).

### Step-by-Step Solution:
Using the dilution formula:
\[
C_1 \times V_1 = C_2 \times V_2
\]

Substitute the known values:
\[
C_1 \times 3 \text{ ml} = 0.06 \text{ M} \times 50 \text{ ml}
\]

Solve for \( C_1 \):
\[
C_1 = \frac{0.06 \times 50}{3} \text{ M}
\]

\[
C_1 = \frac{3}{3} \text{ M} = 1 \text{ M}
\]

### Final Answer:
The concentration of the sodium chloride in the stock solution is **1 M**.

---

Would you like more details on the calculation or further explanations?

Here are some related questions to consider:
1. How would the calculation change if the volume of the stock solution used was different?
2. What if the concentration of the diluted solution was higher, how would that affect the stock concentration?
3. How can you use this dilution formula in laboratory settings?
4. What are some common mistakes to avoid when using the dilution formula?
5. Can you solve for the final volume if the stock concentration and the amount of stock solution used are known?

**Tip:** Always ensure units are consistent when using the dilution formula.

Learn how to calculate the concentration of a sodium chloride stock solution using the dilution formula. Given a diluted solution with a concentration of 0.06 M and a total volume of 50 ml, find the concentration of the stock solution when 3 ml was used. Detailed step-by-step solution provided.

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