The expression \(\log_2 64\) is asking for the power to which 2 must be raised to obtain 64.

\[
\log_2 64 = x \quad \text{means} \quad 2^x = 64
\]

Since \(64 = 2^6\), it follows that:

\[
\log_2 64 = 6
\]

So, \(\log_2 64 = 6\).

Would you like a more detailed explanation or have any questions?

Here are five related questions you might find useful:
1. What is \(\log_2 32\)?
2. How do you solve \(\log_2 128\)?
3. Can you explain \(\log_2\) with other bases like 10 or e?
4. What is the inverse function of \(\log_2 x\)?
5. How does \(\log_2\) relate to binary numbers?

**Tip:** Remember that logarithms are just exponents in reverse! Knowing the basic powers of 2 can make these calculations faster.

Learn how to solve \(\log_2 64\) with a detailed explanation. This problem covers logarithmic concepts, specifically solving for the base 2 logarithm of 64. Suitable for students in Grades 9-12.

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