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This image represents a system of equations where the symbols (soda, fries, pizza) represent unknown values. Here's how we can set up the equations:

1. **First equation (Soda + Fries = 9):**
   \[ S + F = 9 \]
   
2. **Second equation (Two slices of pizza + Fries = 8):**
   \[ 2P + F = 8 \]

3. **Third equation (One slice of pizza + Soda = 7):**
   \[ P + S = 7 \]

We now have three equations:
\[
S + F = 9
\]
\[
2P + F = 8
\]
\[
P + S = 7
\]

Let’s solve this system step by step.

### Step 1: Solve for $ S $ from the third equation:
\[
S = 7 - P
\]

### Step 2: Substitute this value of $ S $ into the first equation:
\[
(7 - P) + F = 9
\]
Simplifying:
\[
F = 2 + P
\]

### Step 3: Substitute $ F = 2 + P $ into the second equation:
\[
2P + (2 + P) = 8
\]
Simplifying:
\[
3P + 2 = 8
\]
\[
3P = 6
\]
\[
P = 2
\]

### Step 4: Substitute $ P = 2 $ back into the expressions for $ S $ and $ F $:
- $ S = 7 - P = 7 - 2 = 5 $
- $ F = 2 + P = 2 + 2 = 4 $

### Final values:
- $ S = 5 $ (Soda)
- $ P = 2 $ (Pizza slice)
- $ F = 4 $ (Fries)

So, the values are:
- **Soda = $5**
- **Pizza slice = $2**
- **Fries = $4**

Would you like further details or have any other questions?

### Related Questions:
1. How can you verify if these values are correct by substituting back into all equations?
2. What method did I use to solve this system of equations?
3. Can this problem be solved graphically? If so, how?
4. What happens if the values of the equations change slightly? How would the solution change?
5. Could this be modeled as a matrix equation? How would you solve it then?

**Tip:** When solving systems of equations, it's often helpful to isolate one variable and substitute it into the other equations to reduce the complexity of the problem.

Solve for the value of soda, fries, and pizza based on the given equations: 
- Soda + Fries = 9 
- 2 slices of Pizza + Fries = 8 
- Pizza + Soda = 7

Learn how to solve a system of equations involving pizza, fries, and soda using substitution. This algebra problem demonstrates step-by-step solutions and is suitable for students in Grades 6-9. Key concepts include solving for unknowns and substitution method.

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