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The problem asks to determine the shear force \(V_x\) at a position \(x = 3.5 \, \text{m}\) from point \(A\) along the beam, which is subjected to different loads. Here's a step-by-step approach to solve this problem:

### Step 1: Identify the Loads
The beam is subject to:
- A point load of 48 kN at \(D\) (located 1.5 m from \(A\)),
- A point load of 8 kN at \(B\) (located 4 m from \(A\)),
- A uniformly distributed load (UDL) of 24 kN/m over a length of 2 m from \(A\).

### Step 2: Support Reactions
Since point \(A\) is fixed, it can provide vertical and horizontal reactions, as well as a moment. Let's denote:
- \(R_A\) as the vertical reaction at point \(A\),
- \(M_A\) as the moment at point \(A\).

We'll start by calculating these reactions using static equilibrium equations.

#### Sum of Vertical Forces:
\[
\sum F_y = 0 \Rightarrow R_A - (24 \times 2) - 48 - 8 = 0
\]
\[
R_A - 48 - 8 - 48 = 0 \Rightarrow R_A =

Para la viga y las cargas mostrada en la figura, hallar Vx=3.5m

Solve for the shear force at a point on a beam subjected to a combination of distributed and point loads. This detailed analysis includes equilibrium equations for calculating support reactions and applying the shear force formula. Ideal for undergraduate engineering students.

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