Draw the shear and moment diagram of a simple beam 5 meters long loaded with a uniformly distributed load of 20 kN/m from midspan to the right end. What is the maximum shear and maximum moment?

Here are the shear force and bending moment diagrams for the beam:

1. **Shear Force Diagram:**
   - From \( A \) to \( C \) (0 to 2.5 m): The shear force is constant at \( +12.5 \) kN.
   - From \( C \) to \( B \) (2.5 to 5 m): The shear force decreases linearly from \( +12.5 \) kN at \( C \) to \( -37.5 \) kN at \( B \).

2. **Bending Moment Diagram:**
   - The moment increases linearly from \( A \) to \( C \), reaching a maximum of \( 31.25 \, \text{kN}\cdot\text{m} \) at \( C \).
   - The moment then decreases to zero at \( B \).

### Summary of Results:
- **Maximum Shear Force:** \( +12.5 \) kN at point \( C \) (2.5 m from the left).
- **Maximum Bending Moment:** \( 31.25 \, \text{kN}\cdot\text{m} \) at point \( C \) (2.5 m from the left).

Would you like further details or have any questions? Here are some related questions:

1. How does changing the location of the load affect the shear and moment diagrams?
2. What would happen if the load was spread over the entire beam instead of half?
3. How can we calculate deflection based on the moment diagram?
4. How would the reactions change if the load was increased?
5. What is the significance of the maximum bending moment in beam design?

**Tip:** Understanding the relationship between shear force and bending moment is crucial in structural analysis and design.

Explore the shear force and bending moment diagrams of a simple beam loaded with a uniformly distributed load of 20 kN/m. Discover the maximum shear force and bending moment at specific points along the beam. Understand the application of equilibrium equations and beam theory in solving this structural analysis problem.

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