Rebecca wants to prove that if the diagonals in a parallelogram are perpendicular, then it is a rhombus. A Parallelogram A B C D. A line connects from points A and C. Another line connects points B and D, intersecting in the middle of the parallelogram. \[A\] \[B\] \[C\] \[D\] Select the appropriate rephrased statement for Rebecca's proof. Choose 1 answer: Choose 1 answer: (Choice A) In quadrilateral \[ABCD\], if \[\overline{AB}\parallel\overline{DC}\] and \[\overline{AD}\parallel\overline{BC}\], then \[\overline{AC}\perp\overline{BD}\] and \[AB=BC=CD=DA\]. A In quadrilateral \[ABCD\], if \[\overline{AB}\parallel\overline{DC}\] and \[\overline{AD}\parallel\overline{BC}\], then \[\overline{AC}\perp\overline{BD}\] and \[AB=BC=CD=DA\]. (Choice B) In quadrilateral \[ABCD\], if \[\overline{AC}\perp\overline{BD}\] and \[AB=BC=CD=DA\], then \[\overline{AB}\parallel\overline{DC}\] and \[\overline{AD}\parallel\overline{BC}\]. B In quadrilateral \[ABCD\], if \[\overline{AC}\perp\overline{BD}\] and \[AB=BC=CD=DA\], then \[\overline{AB}\parallel\overline{DC}\] and \[\overline{AD}\parallel\overline{BC}\]. (Choice C) In quadrilateral \[ABCD\], if \[\overline{AB}\parallel\overline{DC}\], \[\overline{AD}\parallel\overline{BC}\], and \[\overline{AC}\perp\overline{BD}\], then \[AB=BC=CD=DA\]. C In quadrilateral \[ABCD\], if \[\overline{AB}\parallel\overline{DC}\], \[\overline{AD}\parallel\overline{BC}\], and \[\overline{AC}\perp\overline{BD}\], then \[AB=BC=CD=DA\]. (Choice D) In quadrilateral \[ABCD\], if \[AB=BC=CD=DA\], then \[\overline{AB}\parallel\overline{DC}\], \[\overline{AD}\parallel\overline{BC}\], and \[\overline{AC}\perp\overline{BD}\]. D In quadrilateral \[ABCD\], if \[AB=BC=CD=DA\], then \[\overline{AB}\parallel\overline{DC}\], \[\overline{AD}\parallel\overline{BC}\], and \[\overline{AC}\perp\overline{BD}\].