Math Problem Statement
On définit la suite de Fibonacci 〖〖(F〗_n)〗_nϵN par : {█(F_0=0 et F_1=1 @∀n∈N,F_(n+2)=F_n+F_(n+1) )┤ Je veux que tu prouves par récurrence (simple, double, forte) l'affirmation suivante : ∀n≥1,F_n^2-F_(n-1)*F_(n+1)=〖(-1)〗^(n+1)
Solution
Ask a new question for Free
By Image
Drop file here or Click Here to upload
Math Problem Analysis
Mathematical Concepts
Recurrence
Fibonacci Sequence
Inductive Proofs
Formulas
F_n^2 - F_{n-1}F_{n+1} = (-1)^{n+1}
F_{n+2} = F_n + F_{n+1}
Theorems
Principle of Mathematical Induction
Suitable Grade Level
Undergraduate Mathematics (or Advanced High School)
Related Recommendation
Prove the Fibonacci Sequence Recurrence for Natural Numbers
Analysis of Fibonacci Sequence: Growth, Induction, and Limits
Fibonacci Sequence: Proving Strictly Increasing Nature and Lower Bound
Recursive Function C(n) = C(n-1) + 2n - 1: Step-by-Step Solution and Inductive Proof
Prove by Mathematical Induction: 1 + 2 + 2^2 + ... + 2^(n-1) = 2^n - 1