Math Problem Statement
Assinale a alternativa que determina corretamente o calculo da derivada ∂z∂t da função z=3x2y+2xy4 , onde x=sen3t e y=cos2t . Questão 1Escolha uma opção: a. ∂z∂t=(∂z∂x)(∂x∂t)+(∂z∂y)(∂y∂t)=(6y+2y4)(3cos(3t))+(3x2+8xy3)(−2sin(2t))=18cos(3t)xy+6cos(3t)y4−6x2sin(2t)−16xy3sin(2t) b. ∂z∂t=(∂z∂x)(∂x∂t)+(∂z∂y)(∂y∂t)=(6xy+2y4)(3cos(3t))−(3x2+8xy3)(−2sin(4t))=8cos(3t)xy+6cos(3t)y4−6x2sin(2t)−16xy3sin(2t) c. ∂z∂t=(∂z∂x)(∂x∂t)+(∂z∂y)(∂y∂t)=(6xy+2y4)(3cos(3t))+(3x2+8xy3)(−2sin(2t))=18cos(3t)xy+6cos(3t)y4−6x2sin(2t)+16xy3sin(2t) d. ∂z∂t=(∂z∂x)(∂x∂t)+(∂z∂y)(∂y∂t)=(6xy+2y4)(3cos(3t))+(3x2+8xy3)(−2sin(2t))=18cos(3t)xy+6cos(3t)y4−6x2sin(2t)−16xy3sin(2t) e. ∂z∂t=(∂z∂x)(∂x∂t)+(∂z∂y)(∂y∂t)=(6xy+2y4)(3cos(3t))+(3x2+8xy3)(2sin(2t))=18cos(3t)xy+6cos(3t)y4−6x2sin(2t)−16xy3sin(2t)
Solution
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Math Problem Analysis
Mathematical Concepts
Partial Derivatives
Chain Rule
Trigonometric Derivatives
Formulas
∂z/∂t = (∂z/∂x)(∂x/∂t) + (∂z/∂y)(∂y/∂t)
x = sin(3t), y = cos(2t)
∂x/∂t = 3cos(3t), ∂y/∂t = -2sin(2t)
Theorems
Chain Rule for Partial Derivatives
Trigonometric Derivative Rules
Suitable Grade Level
University Level (Calculus II or Multivariable Calculus)
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