i have four consecutive odd numbers. the largest is one less than twice the smallest. which of the follow is the largest of the four numbers

Let the four consecutive odd numbers be represented as follows:
- The smallest number: \( x \)
- The next number: \( x + 2 \)
- The third number: \( x + 4 \)
- The largest number: \( x + 6 \)

According to the given condition, the largest number is one less than twice the smallest number:

\[
x + 6 = 2x - 1
\]

Now, solve this equation:

\[
x + 6 = 2x - 1
\]
\[
6 + 1 = 2x - x
\]
\[
7 = x
\]

So, the smallest number is \( x = 7 \).

The four consecutive odd numbers are:
- 7 (smallest),
- 9,
- 11,
- 13 (largest).

Thus, the largest number is **13**.

Do you need further details or clarification? Here are some related questions to practice:

1. If the largest number were three more than twice the smallest, what would be the largest number?
2. What would be the result if you had consecutive even numbers instead?
3. Can you form a quadratic equation using the consecutive odd numbers?
4. How would the solution change if the largest number were two less than three times the smallest?
5. What would happen if the consecutive numbers were prime instead of odd?

**Tip:** For problems involving consecutive numbers, you can always express them in terms of a variable, simplifying the relationships between them.

Solve the problem of finding the largest of four consecutive odd numbers where the largest is one less than twice the smallest. This algebra problem involves solving a linear equation, suitable for students in Grades 6-8.

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