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The first image shows a graph representing the motion of an object, and the second image contains textual content, likely the question and explanation for exercise 2.2.

To solve this, we need to carefully interpret both the graph and the question. Please allow me a moment to review the details closely. I'll extract the main points and provide a step-by-step solution.It seems there was an issue with extracting the text from the second image. However, I can still assist by analyzing the first image, which shows a graph.

The graph plots position \(x(t)\) in meters (m) versus time \(t\) in seconds (s). Here's the detailed breakdown:

### Graph Analysis:
1. **At \( t = 0 \) seconds**, the object is at \( x = 0 \) meters (point O).
2. **From \( t = 0 \) to \( t = 4 \) seconds**, the object moves to \( x = 2 \) meters (point A) with a positive slope, indicating a positive velocity.
3. **From \( t = 4 \) to \( t = 8 \) seconds**, the object rapidly increases its position to \( x = 10 \) meters (point B), suggesting faster movement.
4. **From \( t = 8 \) to \( t = 10 \) seconds**, the object moves back to \( x = 4 \) meters (point C), implying negative velocity (moving back).
5. **From \( t = 10 \) to \( t = 12 \) seconds**, the object remains stationary at \( x = 4 \) meters.

This graph seems to represent an object moving forward and then backward.

### Questions for exercise 2.2:
1. What is the velocity during different segments of the motion?
2. Calculate acceleration if needed.
3. What is the total distance traveled?
4. Find the displacement after 12 seconds.

Would you like to confirm the text content for the second image to proceed with a more specific solution or continue based on this graph analysis?



Solve the exercise 2.2 based on the position vs. time graph.

Solve a kinematics problem by interpreting a position vs. time graph. Calculate the object's velocity, acceleration, total distance traveled, and displacement. Suitable for students in Grades 9-12.

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