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To solve the problems given, let's first identify the functions:

- \( f(x) = 2x + 1 \)
- \( g(x) = x^3 - 3 \)

Now, let's solve each part:

### a. \( (f \circ g)(x) \) or \( f(g(x)) \)
This means we substitute \( g(x) \) into \( f(x) \).

\[
f(g(x)) = 2(g(x)) + 1
\]

Substituting \( g(x) = x^3 - 3 \):

\[
f(g(x)) = 2(x^3 - 3) + 1
\]
\[
f(g(x)) = 2x^3 - 6 + 1
\]
\[
f(g(x)) = 2x^3 - 5
\]

So, \( (f \circ g)(x) = 2x^3 - 5 \).

### b. \( (g \circ f)(x) \) or \( g(f(x)) \)
This means we substitute \( f(x) \) into \( g(x) \).

\[
g(f(x)) = (f(x))^3 - 3
\]

Substituting \( f(x) = 2x + 1 \):

\[
g(f(x)) = (2x + 1)^3 - 3
\]

To expand \( (2x + 1)^3 \):

\[
(2x + 1)^3 = (2x + 1)(2x + 1)(2x + 1)
\]

Using the binomial expansion:

\[
(2x + 1)^3 = 8x^3 + 12x^2 + 6x + 1
\]

Now, subtract 3:

\[
g(f(x)) = 8x^3 + 12x^2 + 6x + 1 - 3
\]
\[
g(f(x)) = 8x^3 + 12x^2 + 6x - 2
\]

So, \( (g \circ f)(x) = 8x^3 + 12x^2 + 6x - 2 \).

### c. Nilai dari \( (f \circ g)(2) \)
This means we need to substitute \( x = 2 \) into \( f(g(x)) \).

We already have \( f(g(x)) = 2x^3 - 5 \). Substitute \( x = 2 \):

\[
f(g(2)) = 2(2^3) - 5
\]
\[
f(g(2)) = 2(8) - 5
\]
\[
f(g(2)) = 16 - 5 = 11
\]

So, \( (f \circ g)(2) = 11 \).

### Summary of Answers:
a. \( (f \circ g)(x) = 2x^3 - 5 \)  
b. \( (g \circ f)(x) = 8x^3 + 12x^2 + 6x - 2 \)  
c. \( (f \circ g)(2) = 11 \)

Would you like more details on any part of this solution? 

### Related Questions:
1. What is the composition of two different functions?
2. How do you expand a binomial expression?
3. What is the general formula for the binomial theorem?
4. How do you evaluate functions at specific points?
5. What are the properties of polynomial functions?

### Tip:
When dealing with function composition, always substitute the inner function into the outer function carefully to avoid mistakes in algebraic manipulation.

Explore function composition and binomial expansion in mathematics through detailed examples and solutions. Learn how to apply function composition to evaluate composite functions and expand binomials using the binomial expansion formula. Suitable for advanced high school students and anyone interested in advanced algebraic concepts.

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