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To find the number of child tickets sold, let's define the variables based on the information provided:

1. Let \( c \) be the number of child tickets.
2. Let \( s \) be the number of student tickets.
3. Let \( a \) be the number of adult tickets.

From the image and the problem statement:
- The price for each child ticket is £3.
- The price for each student ticket is £5.
- The price for each adult ticket is £6.
- There are 25 more student tickets than child tickets: \( s = c + 25 \).
- There are twice as many adult tickets as child tickets: \( a = 2c \).

The total revenue from ticket sales is £965. Thus, the equation representing the total revenue is:
\[ 3c + 5s + 6a = 965 \]

Substituting the expressions for \( s \) and \( a \) in terms of \( c \) into the revenue equation gives:
\[ 3c + 5(c + 25) + 6(2c) = 965 \]

Simplifying and solving this equation will give the number of child tickets sold. Let's solve it.The number of child tickets sold was 42.

Do you want more details on how this was calculated or do you have any other questions? Here are some further questions you might consider:

1. How many student tickets were sold?
2. How many adult tickets were sold?
3. What was the total revenue from each type of ticket?
4. Can you explain how the equations for this problem were set up?
5. Could you help me with a different ticket pricing problem?

**Tip:** Always double-check the relationships and equations in word problems involving prices and quantities to ensure that all constraints given in the problem statement are correctly used in your calculations.

25 more student tickets than child tickets were sold. 2 times as many adult tickets as child tickets were sold. The theatre received a total of £965 from ticket sales. How many child tickets were sold?

Learn how to calculate the number of child tickets sold when given a total revenue and relationships between student, adult, and child ticket sales. This algebraic problem involves setting up linear equations and solving for the unknown variable.

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