Solve for Y in 10x-(1/3)y=15 the parentheses indicate that it’s a fractuon

We are given the equation:

\[
10x - \frac{1}{3}y = 15
\]

To solve for \( y \), follow these steps:

1. **Isolate the term involving \( y \):**

\[
- \frac{1}{3}y = 15 - 10x
\]

2. **Multiply both sides of the equation by \(-3\)** to eliminate the fraction:

\[
y = -3(15 - 10x)
\]

3. **Distribute the \(-3\):**

\[
y = -45 + 30x
\]

Thus, the solution for \( y \) is:

\[
y = 30x - 45
\]

Would you like further details or clarification?

Here are 5 related questions for further exploration:
1. How would the solution change if the equation was \( 10x + \frac{1}{3}y = 15 \)?
2. Can you find the value of \( y \) when \( x = 2 \)?
3. How can we graph the equation after solving for \( y \)?
4. What would the equation look like if both sides were multiplied by 3 from the start?
5. Can you rewrite the equation in slope-intercept form?

**Tip:** When solving for a variable, it's helpful to eliminate fractions early to simplify the process.

Solve for Y in 10x-(1/3)y=15 the parentheses indicate that it’s a fraction

Learn how to solve the linear equation 10x - (1/3)y = 15 by isolating y. This problem covers algebraic concepts such as solving for a variable, handling fractions, and using the distributive property. Suitable for students in Grades 8-10.

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