We are given the equation:

\[
\frac{\frac{250 - 25}{15}}{x} = \frac{450 - 6}{130}
\]

Let's solve for \( x \) step by step.

### Step 1: Simplify both sides
1. Simplify the numerator and denominator of the fractions.

\[
250 - 25 = 225 \quad \text{and} \quad 450 - 6 = 444
\]

So the equation becomes:

\[
\frac{\frac{225}{15}}{x} = \frac{444}{130}
\]

### Step 2: Simplify the fractions

\[
\frac{225}{15} = 15 \quad \text{and} \quad \frac{444}{130} = \frac{222}{65}
\]

Now the equation is:

\[
\frac{15}{x} = \frac{222}{65}
\]

### Step 3: Solve for \( x \)

To solve for \( x \), cross-multiply:

\[
15 \times 65 = 222 \times x
\]

\[
975 = 222x
\]

Now, divide both sides by 222:

\[
x = \frac{975}{222} = 4.39 \quad (\text{rounded to 2 decimal places})
\]

Thus, the value of \( x \) is approximately \( 4.39 \).

---

Would you like a more detailed explanation of any step?

Here are 5 related questions you could explore:
1. What is cross-multiplication, and how is it applied in equations with fractions?
2. How would the solution change if the numbers in the equation were different?
3. How can the accuracy of rounding be improved in mathematical calculations?
4. What are other ways to solve an equation with fractions?
5. What would happen if we multiplied both sides of the equation by the least common denominator (LCD)?

**Tip:** Always double-check your simplifications, as errors in arithmetic can lead to incorrect results later in the solution!

Learn how to solve the fractional equation ((250-25)/15)/x = (450-6)/130 step-by-step using cross multiplication. This problem involves simplification of fractions and applying algebraic methods to find x, suitable for students in Grades 8-10.

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