To solve the system of linear equations:

1. \( 2,3y + 3z = 6600 \)
2. \( 3y + z = 1 \)

### Step 1: Simplify the equations.
Firstly, rewrite the first equation in a standard format by expressing \( 2,3y \) as \( 2.3y \):

1. \( 2.3y + 3z = 6600 \)
2. \( 3y + z = 1 \)

### Step 2: Solve the second equation for \( z \).
From the second equation, solve for \( z \):

\[
z = 1 - 3y
\]

### Step 3: Substitute \( z \) in the first equation.
Substitute \( z = 1 - 3y \) into the first equation:

\[
2.3y + 3(1 - 3y) = 6600
\]

### Step 4: Simplify and solve for \( y \).
Expand and simplify the equation:

\[
2.3y + 3 - 9y = 6600
\]

Combine like terms:

\[
-6.7y + 3 = 6600
\]

Subtract 3 from both sides:

\[
-6.7y = 6597
\]

Divide by -6.7:

\[
y = \frac{6597}{-6.7} \approx -984
\]

### Step 5: Substitute \( y \) back to find \( z \).
Substitute \( y \approx -984 \) back into the equation \( z = 1 - 3y \):

\[
z = 1 - 3(-984) = 1 + 2952 = 2953
\]

### Final Answer:
- \( y \approx -984 \)
- \( z \approx 2953 \)

Would you like more details or have any questions?

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Here are 5 related questions:
1. How would you solve this system using the substitution method?
2. What are the implications if \( z \) were negative?
3. Can you solve a similar system with different coefficients?
4. How does the presence of decimals in coefficients affect the solution process?
5. What is the geometric interpretation of this system of equations?

**Tip:** Always check your solutions by substituting them back into the original equations to ensure accuracy.

Learn how to solve the system of linear equations 2.3y + 3z = 6600 and 3y + z = 1 using the substitution method. This problem covers key algebraic concepts, including linear equations and substitution. Suitable for students in Grades 7-9.

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