Let's solve the equation step by step.

The given equation is:

\[
-2(1 + 8s) = -3(2s + 4)
\]

### Step 1: Distribute the constants on both sides of the equation.

Distribute \(-2\) on the left side:

\[
-2 \times 1 - 2 \times 8s = -2 - 16s
\]

Distribute \(-3\) on the right side:

\[
-3 \times 2s - 3 \times 4 = -6s - 12
\]

So the equation now becomes:

\[
-2 - 16s = -6s - 12
\]

### Step 2: Combine like terms.

Move all terms involving \(s\) to one side and constant terms to the other side. We can do this by adding \(16s\) to both sides and adding 12 to both sides:

\[
-2 + 12 = -6s + 16s
\]

This simplifies to:

\[
10 = 10s
\]

### Step 3: Solve for \(s\).

Divide both sides by 10:

\[
s = \frac{10}{10} = 1
\]

So, the solution is:

\[
s = 1
\]

Would you like more details or have any questions?

### Related Questions:

1. How do you distribute a negative sign across parentheses?
2. What is the method to move terms involving variables to one side of an equation?
3. How do you handle equations where both sides contain variables?
4. Can you explain the importance of isolating the variable in an equation?
5. What steps are involved in checking if your solution is correct?
6. How do you solve linear equations with coefficients?
7. What is the role of inverse operations in solving equations?
8. Can you explain how to deal with equations that have the same variable on both sides?

**Tip:** Always combine like terms carefully and keep track of the signs to avoid errors in your calculations.

Learn how to solve the linear equation -2(1 + 8s) = -3(2s + 4) with detailed step-by-step instructions. This problem covers linear equations and the distributive property. Suitable for students in Grades 7-9.

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