To solve the equation \( 9(5)x = 41 \), it appears that there's a possible confusion in notation. If you mean \( 9 \times (5x) = 41 \), then we can proceed as follows:

1. Start with the given equation:
   \[ 9(5)x = 41 \]

2. Simplify the left side:
   \[ 45x = 41 \]

3. Now, solve for \( x \) by dividing both sides of the equation by 45:
   \[ x = \frac{41}{45} \]

So, the value of \( x \) is:

\[ x = \frac{41}{45} \]

Calculating this value:

\[ x \approx 0.9111 \]

Thus, \( x \approx 0.9111 \) (rounded to four decimal places).

Would you like any further details or have any other questions?

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### Related Questions

1. How would you solve the equation \( 9(5x + 2) = 41 \)?
2. What is the value of \( x \) in the equation \( 5x + 7 = 41 \)?
3. If \( x = 0.9111 \), what is the value of \( 9(5x) \)?
4. How do you solve the equation \( 3x = 9 \)?
5. What is the general approach to solving linear equations?
6. How would the solution change if the equation were \( 45x = 41 + 4 \)?
7. What is the value of \( x \) if the equation were \( 45x = 50 \)?
8. How do you verify the solution to a linear equation?

**Tip:** Always check your solution by substituting it back into the original equation to ensure it satisfies the equation.

Learn how to solve the linear equation 9(5)x = 41 with a detailed step-by-step solution. This problem involves basic algebraic manipulation and solving linear equations. Suitable for students in Grades 7-9.

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