🕯️× 4 =  __
 5  -🕯️=  __
🕯️×🕯️+ 1 =  __
🕯️÷🕯️=  __
🕯️+🕯️+🕯️=  __
🕯️-  1 =  __

Let's represent the candle symbol "🕯️" with a variable, say \( x \). Then the expressions can be written and solved as follows:

1. \( x \times 4 = 4x \)
2. \( 5 - x \)
3. \( x \times x + 1 = x^2 + 1 \)
4. \( x \div x = 1 \) (since any non-zero number divided by itself equals 1)
5. \( x + x + x = 3x \)
6. \( x - 1 \)

So the solutions in terms of \( x \) are:

1. \( 4x \)
2. \( 5 - x \)
3. \( x^2 + 1 \)
4. \( 1 \)
5. \( 3x \)
6. \( x - 1 \)

If you want to solve these for a specific value of \( x \), just provide the value of \( x \).

Would you like to solve these for a specific value or have more details? 

Here are some related questions:

1. What happens if \( x \) is zero in all these expressions?
2. How do these equations change if \( x \) is a negative number?
3. Can you find \( x \) if you know that \( 4x = 20 \)?
4. What would be the result if \( x = 2 \)?
5. How can you express \( 5 - x = 0 \)?
6. If \( x \) is a fraction, how do the results differ?
7. Can you interpret these results graphically on a coordinate plane?
8. How does \( x^2 + 1 \) behave as \( x \) increases?

**Tip:** When dealing with algebraic expressions, try substituting different values for the variable to see how the outcome changes. This can give you a better understanding of the equation's behavior.

Learn how to solve equations involving candle symbols (represented as variables) with step-by-step solutions. This problem covers basic arithmetic and algebraic concepts, suitable for students in Grades 4-6.

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