Math Problem Statement
Un alambre de 80m de largo se va a partir en dos pedazos una de las partes se doblara para formar una circunferencia y la otra un triángulo equilátero ¿ Cómo se debe cortar el alambre para la suma de las áreas del círculo y del triángulo sean maximas
Solution
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Math Problem Analysis
Mathematical Concepts
Geometry
Optimization
Differentiation
Formulas
Circumference formula: x = 2πr
Area of a circle: A = πr^2
Area of an equilateral triangle: A = (√3/4)L^2
Optimization through differentiation
Theorems
Optimization of functions
Area formulas
Suitable Grade Level
Grades 10-12
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