Let's break down the inequality:  
We are given two inequalities to consider:

1. \( \pi < 4 \)
2. \( \pi^2 < 16 \)

### Step 1: Analyze \( \pi < 4 \)

We know the approximate value of \( \pi \) is about 3.1416.  
Since \( 3.1416 < 4 \), the first part of the inequality \( \pi < 4 \) is true.

### Step 2: Analyze \( \pi^2 < 16 \)

Now, let's calculate \( \pi^2 \):

\[
\pi^2 \approx 3.1416^2 = 9.8696
\]

Since \( 9.8696 < 16 \), the second part of the inequality \( \pi^2 < 16 \) is also true.

### Conclusion:
Both inequalities are true:  
- \( \pi < 4 \) is true.  
- \( \pi^2 < 16 \) is true.  
Thus, the compound statement \( \pi < 4 \) and \( \pi^2 < 16 \) is valid.

Would you like more details or have any questions?

Here are 5 related questions to explore:
1. What would happen if we squared both sides of the inequality \( \pi < 4 \)?
2. How do we interpret inequalities involving irrational numbers like \( \pi \)?
3. Can we compare other irrational numbers like \( e \) in similar inequalities?
4. What are the properties of squaring inequalities, and how do they affect results?
5. Can you derive an inequality involving \( \pi^3 \) instead of \( \pi^2 \)?

**Tip:** When working with inequalities involving irrational numbers, it's often useful to approximate their values and compare them with rational numbers for clarity.

Understand how to solve and interpret the inequalities π < 4 and π² < 16 using approximation and squaring methods. This guide breaks down the mathematical reasoning behind inequalities involving irrational numbers like π, ideal for students in Grades 8-10.

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