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Löse mir diese Aufgabe F1 ist 180N und F2 auch 180N

The problem provided involves a belt drive, with forces \( F_1 = 180 \, \text{N} \) and \( F_2 = 180 \, \text{N} \) acting on the belt. The angle \( \alpha \) between the forces is \( 30^\circ \). The task is to find the magnitude and direction of the resultant bearing force \( F_L \) graphically, using a scale where 1 mm corresponds to 2 N.

### Steps to Solve:

1. **Draw the Forces**: Start by drawing the two forces \( F_1 \) and \( F_2 \) at the correct angle \( \alpha = 30^\circ \) between them, using the given scale.

2. **Find the Resultant Force**:
   - Use the parallelogram method or the triangle method to graphically find the resultant force \( F_L \).
   - According to the scale, \( 1 \, \text{mm} = 2 \, \text{N} \), so you will draw the forces \( F_1 \) and \( F_2 \) as lines of 90 mm each (since \( 180 \, \text{N} / 2 \, \text{N/mm} = 90 \, \text{mm} \)).

3. **Measure the Resultant Force**:
   - After drawing, measure the length of the resultant force \( F_L \) in millimeters.
   - Convert this length back to Newtons using the scale.

4. **Determine the Direction**:
   - Measure the angle between the resultant force and a reference direction (typically one of the forces or a horizontal line).

Would you like to proceed with a detailed solution or a sketch demonstrating the graphical method?

Learn how to use the graphical method to find the resultant force in a belt drive problem with forces of 180N each at an angle of 30 degrees. Step-by-step solution including drawing forces to scale, finding resultant force length, and determining direction.

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