Math Problem Statement
Find the indefinite integral: integral fraction numerator e to the power of 7 x end exponent over denominator e to the power of 7 x end exponent plus 36 end fraction d x 1 over 7 ln left parenthesis e to the power of 7 x end exponent plus 36 right parenthesis plus c 1 over 7 e to the power of 7 x end exponent left parenthesis e to the power of 7 x end exponent plus 36 right parenthesis plus c 7 e to the power of 7 x end exponent ln left parenthesis e to the power of 7 x end exponent plus 36 right parenthesis plus C 7 ln left parenthesis e to the power of 7 x end exponent plus 36 right parenthesis plus c
Solution
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Math Problem Analysis
Mathematical Concepts
Integration
Substitution Method
Formulas
Integral of reciprocal function: \( \int \frac{1}{u} \, du = \ln |u| + C \)
Theorems
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Suitable Grade Level
College Level