The expression you provided is:

\[
441x^2y^2 - 9m^4
\]

This is a difference of two squares, which can be factored using the identity:

\[
a^2 - b^2 = (a - b)(a + b)
\]

Here, we can rewrite the given expression in a suitable form:

\[
441x^2y^2 = (21xy)^2 \quad \text{and} \quad 9m^4 = (3m^2)^2
\]

Thus, the expression becomes:

\[
(21xy)^2 - (3m^2)^2
\]

Now, applying the difference of squares formula:

\[
(21xy - 3m^2)(21xy + 3m^2)
\]

So, the factored form of the expression \(441x^2y^2 - 9m^4\) is:

\[
(21xy - 3m^2)(21xy + 3m^2)
\]

Would you like more details on the factorization process or have any questions?

### Related Questions:
1. How do you identify a difference of squares in more complex expressions?
2. Can you apply this factorization method to a cubic expression?
3. What happens if \(x\), \(y\), or \(m\) equals zero in the factored form?
4. How can you solve an equation with the factorized form?
5. What are other common factoring identities beyond the difference of squares?

### Tip:
When dealing with polynomials, always check if the expression can be simplified or factored using identities like the difference of squares, perfect square trinomials, or sum/difference of cubes.

Discover how to factor the expression 441x^2y^2 - 9m^4 by applying the difference of squares method. This algebraic concept breaks down the expression into (21xy - 3m^2)(21xy + 3m^2), providing a clear step-by-step solution. Ideal for students in Grades 9-11.

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