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This is a physics problem involving diffraction or interference patterns, likely using the formula for double-slit interference. Based on the image and its markings, here's the breakdown of the information provided:

- **Slit separation \( d = 0.6 \, \text{mm} = 0.6 \times 10^{-3} \, \text{m} \)**
- **Screen distance \( D = 2.5 \, \text{m} \)**
- **Fringe separation \( \Delta y = 2.27 \, \text{mm} = 2.27 \times 10^{-3} \, \text{m} \)**

### Formula to calculate wavelength \( \lambda \):
In a double-slit experiment, the wavelength \( \lambda \) of light is given by the formula:
\[
\lambda = \frac{d \cdot \Delta y}{D}
\]
Where:
- \( d \) is the distance between the slits,
- \( \Delta y \) is the fringe separation (the distance between two consecutive bright or dark fringes),
- \( D \) is the distance from the slits to the screen.

### Let's calculate the wavelength \( \lambda \).

I will now calculate the result.The wavelength of the light \( \lambda \) is approximately \( 5.45 \times 10^{-7} \, \text{m} \) or 545 nm, which corresponds to green light in the visible spectrum.

Do you have any questions, or would you like further details on this calculation?

Here are 5 related questions you can explore:
1. How does the wavelength affect the fringe separation in a double-slit experiment?
2. What happens to the interference pattern if the distance between the slits is increased?
3. How would the interference pattern change if a different color of light was used?
4. What is the relationship between the wavelength and the diffraction angle?
5. Can the double-slit experiment be used to determine the speed of light?

**Tip:** In wave interference problems, it's crucial to keep units consistent throughout the calculations to avoid errors!

A light source passes through a green filter, and the light is diffracted through two slits with a distance of 0.60 mm apart. The interference pattern is projected onto a screen 2.5 meters away, where the distance between two consecutive bright fringes is measured as 2.27 mm. Calculate the wavelength of the incident light.

Learn how to calculate the wavelength of light using the double-slit experiment formula. In this example, light passes through slits 0.60 mm apart and is projected onto a screen 2.5 meters away, with fringe separation of 2.27 mm. This problem applies principles of wave interference and diffraction.

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