This is a proportion problem, and we can solve it by setting up a ratio:

\[
\frac{7}{0.125} = \frac{9}{x}
\]

We now need to solve for \( x \). To do this, we cross-multiply:

\[
7 \cdot x = 9 \cdot 0.125
\]

Simplifying the right-hand side:

\[
7x = 9 \times 0.125 = 1.125
\]

Now, divide both sides by 7 to isolate \( x \):

\[
x = \frac{1.125}{7} = 0.1607 \, (\text{approximately})
\]

Thus, \( x \approx 0.1607 \).

Would you like further details on any part of this? Here are some related questions for practice:

1. What is the ratio between 7 and 9?
2. How do you calculate proportions in general?
3. If 9 is to \( x \) as 7 is to 0.125, what would happen if 9 were replaced by another number?
4. How do you check if two ratios are equal?
5. Can proportions be applied to more complex equations?

**Tip**: When solving proportions, cross-multiplication is a quick and reliable method.

This page explains how to solve the proportion problem: 7 is to 0.125 as 9 is to X. Using cross-multiplication, we determine that X is approximately 0.1607. This example illustrates basic concepts in ratios and proportions, suitable for students in Grades 6-8.

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