Thank you for the clarification. Let's solve the problem using the correct function:

### 1. **Function Image and Preimage**
   - **Function**: \( y = \frac{9x - 3}{2x} \)
   - **Find the image of \( x = 10 \)** and **the preimage of \( y = 23 \)**.

**Solution:**

1. **Image of \( x = 10 \)**:
   \[
   y = \frac{9(10) - 3}{2(10)} = \frac{90 - 3}{20} = \frac{87}{20} = 4.35
   \]
   So, the image of \( x = 10 \) is \( y = 4.35 \).

2. **Preimage of \( y = 23 \)**:
   \[
   23 = \frac{9x - 3}{2x}
   \]
   To solve for \( x \), multiply both sides by \( 2x \):
   \[
   23 \cdot 2x = 9x - 3
   \]
   \[
   46x = 9x - 3
   \]
   Move all terms involving \( x \) to one side:
   \[
   46x - 9x = -3
   \]
   \[
   37x = -3 \quad \Rightarrow \quad x = \frac{-3}{37}
   \]
   So, the preimage of \( y = 23 \) is \( x = \frac{-3}{37} \approx -0.081 \).

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Explore how to solve the rational function problem y = (9x - 3)/(2x) with detailed steps and solutions. Learn about rational functions, including finding images and preimages. Suitable for advanced high school students in Grades 11-12.

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