Let's solve the given expression step-by-step:

\[
(-2) \cdot (-2)^3 \cdot (-2)^2
\]

1. **Calculate \((-2)^3\):**  
   \[
   (-2)^3 = (-2) \times (-2) \times (-2) = 4 \times (-2) = -8
   \]

2. **Calculate \((-2)^2\):**  
   \[
   (-2)^2 = (-2) \times (-2) = 4
   \]

3. **Substitute these values back into the original expression:**

   \[
   (-2) \cdot (-8) \cdot 4
   \]

4. **Multiply from left to right:**

   - First, \((-2) \cdot (-8)\):

     \[
     (-2) \cdot (-8) = 16
     \]

   - Then, \(16 \cdot 4\):

     \[
     16 \cdot 4 = 64
     \]

Therefore, the result of the expression \((-2) \cdot (-2)^3 \cdot (-2)^2\) is:

\[
\boxed{64}
\]

Would you like more details or have any questions? Here are some related questions to explore this topic further:

1. What is the value of \((-3)^4 \cdot (-3)^2\)?
2. How do you simplify \((-2)^4 \cdot (-2)^3\)?
3. What is the result of \((-1)^5 \cdot (-1)^3\)?
4. How do you calculate \((-4) \cdot (-4)^2 \cdot (-4)^3\)?
5. What is the value of \((-5)^3 \cdot (-5)^2\)?

**Tip:** When working with exponents and negative numbers, remember that an even power results in a positive number, while an odd power results in a negative number.

Learn how to solve the expression (-2) * (-2)^3 * (-2)^2 with a detailed step-by-step solution. This problem involves exponents and multiplication of negative numbers. Suitable for students in Grades 7-9.

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