https://r2.erweima.ai/mathbot/image/172587978775271lvrfdk.jpg

The task here is to find and solve linear equations for each part of the problem in the image. Let’s solve each one by one.

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### **a) Sabine buys roses for 0.80 € and anemones for 0.50 €. She spends 7 €.**

Let:
- \( x \) be the number of roses,
- \( y \) be the number of anemones.

We can form the equation:
\[
0.80x + 0.50y = 7
\]
A possible solution can be obtained by solving for different values of \( x \) and \( y \) (assuming whole numbers). For example:
- If \( x = 5 \), substituting in the equation:
\[
0.80(5) + 0.50y = 7 \Rightarrow 4 + 0.50y = 7 \Rightarrow 0.50y = 3 \Rightarrow y = 6
\]
So, Sabine could have bought 5 roses and 6 anemones.

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### **b) Three scoops of ice cream and one portion of cream cost 2.30 €.**

Let:
- \( x \) be the cost of one scoop of ice cream,
- \( y \) be the cost of one portion of cream.

The equation is:
\[
3x + y = 2.30
\]
A possible solution:
- If \( x = 0.60 \), then:
\[
3(0.60) + y = 2.30 \Rightarrow 1.80 + y = 2.30 \Rightarrow y = 0.50
\]
Thus, one scoop of ice cream costs 0.60 €, and one portion of cream costs 0.50 €.

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### **c) The sum of twice one number and three times another number equals 48.**

Let:
- \( x \) be the first number,
- \( y

Drei Kugeln Eis und eine Portion Sahne kosten 2,30 €.

Learn how to solve a linear equation where the cost of three scoops of ice cream and one portion of cream totals 2.30 €. This problem involves basic algebra and linear equations, suitable for students in Grades 5-7.

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