Math Problem Statement
Soit la suite U(n) définie sur l'ensemble N par U(0)=2 et U(n+1)=2/3*U(n)+(1/3*n)+1. Pour tout entier naturel n, on a u(n)≤n+3. On a aussi u(n+1)-u(n)=1/3(n+3-u(n)). De plus, on a la suite géométrique de raison 2/3 suivante : v(n)=u(n)-n. En déduire que pour tout entier naturel n, u(n)=2*(2/3)^n+n.
Solution
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Math Problem Analysis
Mathematical Concepts
Recurrence Relations
Geometric Sequences
Algebra
Formulas
U(n+1) = (2/3) * U(n) + (1/3) * n + 1
v(n+1) = (2/3) * v(n)
v(n) = 2 * (2/3)^n
Theorems
Geometric Sequence Theorem
Recurrence Relation Solutions
Suitable Grade Level
Grades 11-12
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