Here's the graph of the equation \( y = x^2 + 2x + 1 \). The parabola opens upwards, with its vertex at \( (-1, 0) \) and the y-intercept at \( (0, 1) \).

Do you have any questions or need further details?

Here are some related questions:
1. How do you find the x-intercepts of this graph?
2. What is the significance of the vertex in this parabola?
3. How does the graph change if we modify the equation to \( y = x^2 + 2x + c \)?
4. What role does the coefficient of \( x^2 \) play in the shape of the graph?
5. How can you determine the axis of symmetry from the graph?

**Tip:** When graphing a quadratic function, identifying the vertex and intercepts can make sketching the graph much easier.

Explore the graph of the quadratic equation y = x^2 + 2x + 1. Understand its vertex at (-1, 0), y-intercept at (0, 1), and how to find x-intercepts. Learn about the significance of the vertex, how modifying the equation affects the graph, and the role of the coefficient of x^2.

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