Given that the circle is tangent to the y-axis and has its center at \((-2, -3)\), we can deduce the radius and then write the equation of the circle.

### Key points:
1. **Center**: The center of the circle is at \((-2, -3)\).
2. **Tangent to the y-axis**: This means the distance from the center to the y-axis is equal to the radius of the circle.

### Steps:

1. **Distance to the y-axis**: The distance from the center of the circle to the y-axis is the absolute value of the x-coordinate of the center, which is \(|-2| = 2\). Therefore, the radius \(r = 2\).

2. **Equation of the circle**: The general equation of a circle is \((x - h)^2 + (y - k)^2 = r^2\), where \((h, k)\) is the center and \(r\) is the radius.

Substituting the given values:
- Center \((h, k) = (-2, -3)\)
- Radius \(r = 2\)

The equation becomes:
\[
(x + 2)^2 + (y + 3)^2 = 2^2
\]
\[
(x + 2)^2 + (y + 3)^2 = 4
\]

This is the equation of the circle.

Would you like more details or have any questions?

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Here are some related questions to consider:

1. How do you find the radius of a circle if you know it's tangent to a specific axis?
2. What changes in the circle's equation if it's tangent to the x-axis instead?
3. How do you calculate the distance between a point and a line?
4. What happens to the circle's equation if the center moves to the origin?
5. How do you determine the equation of a circle given two tangents and the radius?
6. Can a circle be tangent to both the x-axis and the y-axis simultaneously? What would its equation be?
7. How do you find the area of a circle given its radius?
8. What is the equation of a circle if the radius is doubled but the center remains the same?

**Tip**: The distance between any point and the y-axis (or x-axis) is simply the absolute value of the corresponding coordinate.

Learn how to find the equation of a circle tangent to the y-axis at the point (-2, -3). This problem involves circle geometry and the derivation of circle equations from geometric conditions. Suitable for high school students studying geometry and algebra.

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