Assinale a alternativa que determina corretamente o calculo da integral ∫1−1∫30x2−3y−7dxdy Questão 1Escolha uma opção: a. ∫1−1∫30x2−3y−7dxdy=∫1−1[x33−(3y−7)x]30dy=∫1−19y−12dy=−24 b. ∫1−1∫30x2−3y−7dxdy=∫1−1[x33−(3y+7)x]03dy=∫1−1−9y−12dy=−24 c. ∫1−1∫30x2−3y−7dxdy=∫1−1[x33−(3y+7)x]30dy=∫1−1−9y−12dy=−24 d. ∫1−1∫30x2−3y−7dxdy=∫1−1[x33+(3y+7)x]30dy=∫1−1−9y−12dy=−24 e. ∫1−1∫30x2−3y−7dydx=∫1−1[x33−(3y+7)x]30dy=∫1−1−9y−12dy=−24