To differentiate \( y = 2^x \) with respect to \( x \), we can use the chain rule and the fact that the derivative of \( a^x \) with respect to \( x \) is \( a^x \ln(a) \), where \( a \) is a constant.

Here are the steps:

1. Recognize that \( y = 2^x \).
2. Use the formula for the derivative of an exponential function \( a^x \): 
\[ \frac{d}{dx} (a^x) = a^x \ln(a) \]

Applying this to \( y = 2^x \):

\[ \frac{dy}{dx} = 2^x \ln(2) \]

So, the derivative of \( y = 2^x \) is:

\[ \frac{dy}{dx} = 2^x \ln(2) \]

Would you like more details or have any questions about this differentiation? 

Here are 5 questions you might want to ask next:
1. How do you differentiate \( y = e^{3x} \)?
2. What is the integral of \( y = 2^x \)?
3. Can you explain the chain rule in more detail?
4. How do you differentiate \( y = \sin(x^2) \)?
5. What is the derivative of \( y = \ln(x) \)?

**Tip:** When differentiating exponential functions, remember to multiply by the natural logarithm of the base.

Learn how to differentiate the function y = 2^x using the chain rule and the derivative formula of exponential functions. This problem is suitable for advanced high school students and covers key concepts such as exponential functions and logarithms.

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