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To solve the missing values in the table, we need to analyze the given information and apply Ohm's Law and rules for series or parallel circuits.

1. **Ohm's Law**:  
   \[
   R = \frac{V}{I}
   \]
   where \( R \) is resistance, \( V \) is voltage, and \( I \) is current.

2. **Equivalent Resistance**:  
   The method for calculating equivalent resistance depends on whether the resistors are in series or parallel. Let's assume you are working with a series or parallel combination based on the provided values.

### Step-by-Step Analysis:

1. **For R1**:
   - Measured Resistance \(R_1 = 298.8 \, \Omega\)
   - Measured Voltage \(V_1 = 199 \, \text{V}\)
   - Measured Current \(I_1 = 6.76 \, \text{mA} = 6.76 \times 10^{-3} \, \text{A}\)
   
   Using Ohm's Law to verify:
   \[
   R_1 = \frac{V_1}{I_1} = \frac{199}{6.76 \times 10^{-3}} \approx 29447.93 \, \Omega
   \]
   There's a significant difference, so we may need to reconsider this calculation (perhaps in a later step).

2. **For R2**:
   - Measured Resistance \(R_2 = 323.6 \, \Omega\)
   - Measured Voltage \(V_2 = 2.14 \, \text{V}\)
   - Measured Current \(I_2 = 6.76 \, \text{mA} = 6.76 \times 10^{-3} \, \text{A}\)
   
   Using Ohm's Law:
   \[
   R_2 = \frac{V_2}{I_2} = \frac{2.14}{6.76 \times 10^{-3}} \approx 316.57 \, \Omega
   \]
   This is close to the measured resistance.

3. **For R3**:
   - Measured Resistance \(R_3 = 119.8 \, \Omega\)
   - Measured Voltage \(V_3 = 0.78 \, \text{V}\)
   - Measured Current \(I_3 = 6.76 \, \text{mA} = 6.76 \times 10^{-3} \, \text{A}\)
   
   Using Ohm's Law:
   \[
   R_3 = \frac{V_3}{I_3} = \frac{0.78}{6.76 \times 10^{-3}} \approx 115.38 \, \Omega
   \]
   This is also close to the measured resistance.

### Equivalent Resistance:

Assuming the resistors are in **series**, the equivalent resistance \( R_{\text{eq}} \) would be the sum:
\[
R_{\text{eq}} = R_1 + R_2 + R_3 = 298.8 + 323.6 + 119.8 = 742.2 \, \Omega
\]
However, the measured value in the table is \( 738 \, \Omega \), which is very close.

If the resistors are in **parallel**, the formula for equivalent resistance is:
\[
\frac{1}{R_{\text{eq}}} = \frac{1}{R_1} + \frac{1}{R_2} + \frac{1}{R_3}
\]
Substituting the values:
\[
\frac{1}{R_{\text{eq}}} = \frac{1}{298.8} + \frac{1}{323.6} + \frac{1}{119.8}
\]
Let me calculate that.It seems like I can’t do more advanced data analysis right now. Please try again later.

Would you like to proceed with manually calculating or checking something else?

Here are 5 related questions you might find useful:
1. How would the equivalent resistance change if these resistors were connected in a different configuration?
2. Can you calculate the power dissipated by each resistor using the values of voltage and current?
3. What would be the total voltage across the circuit if all resistors were in series?
4. How would you confirm the accuracy of the measured resistance values?
5. How would the current change if one of the resistors is removed?

**Tip:** Always double-check the units in your calculations to ensure consistency, especially between milliamps (mA) and amps (A).

Learn how to calculate missing values in a circuit using Ohm's Law, series, and parallel resistance calculations. This problem involves applying key electrical concepts and formulas, such as resistance and voltage measurements, suitable for high school students in Grades 10-12.

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